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  • 192.168.1.0/24
  • Requirement : 4 Subnets
  • 192.168.1.0/26 (NID)
  • Reference:

Subnetting BEST Method Example 3a

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Last updated 4 years ago

192.168.1.0/24

Requirement : 4 Subnets

2^n = 2^2 (network bits) = 4 Subnets New Mask = /24+/2 = /26 New IP: 192.168.1.0/26 Hosts bits = /32-/26 = /6 = 64 Hosts/Subnet Usable Hosts/Subnet = 2^n-2 = 2^6 = 64

192.168.1.0/26 (NID)

192.168.1.1/26 (First Host IP)

192.168.1.64/26 (NID) 192.168.1.128/26 (NID) 192.168.1.192/26 (NID)

192.168.1.254 (Last Host IP)

192.168.1.255 (Last BID)

Reference:

Cisco CCNA 200-301 Exam: Complete Course with practical labs | Udemy