Subnetting BEST Method Example 3c
From the Last Subnet of 192.168.1.112/26 (i.e. 192.168.1.64-192.168.1.127) used previously we need 2 Hosts/Subnet
192.168.1.112/26
Requirement : 2 Hosts/Subnet
2^X = 2^2 = 4 Hosts/Subnet Usable Hosts = 2^n (host bits) -2 = 2^2-2 = 4-2 = 2 Usable Hosts/Subnet New Mask = /32-/2 = /30 New IP: 192.168.1.112/30
192.168.1.112/30 (First NID)
192.168.1.113/30 (First Host IP)
192.168.1.114/30 (Second IP) 192.168.1.115/30 (BID)
192.168.1.116/30 (NID)
192.168.1.120/30 (NID)
192.168.1.124/30 (Last NID)
192.168.1.127/26 (Last BID)
192.168.1.128
Reference:
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