Subnetting BEST Method Example 3c

From the Last Subnet of 192.168.1.112/26 (i.e. 192.168.1.64-192.168.1.127) used previously we need 2 Hosts/Subnet

192.168.1.112/26

Requirement : 2 Hosts/Subnet

2^X = 2^2 = 4 Hosts/Subnet Usable Hosts = 2^n (host bits) -2 = 2^2-2 = 4-2 = 2 Usable Hosts/Subnet New Mask = /32-/2 = /30 New IP: 192.168.1.112/30

192.168.1.112/30 (First NID)

192.168.1.113/30 (First Host IP)

192.168.1.114/30 (Second IP) 192.168.1.115/30 (BID)

192.168.1.116/30 (NID)

192.168.1.120/30 (NID)

192.168.1.124/30 (Last NID)

192.168.1.127/26 (Last BID)

192.168.1.128

Reference:

• Cisco CCNA 200-301 Exam: Complete Course with practical labs | Udemy