Subnetting BEST Method Example 3b

From the Subnet of 192.168.1.64/26 (i.e. 192.168.1.64-192.168.1.127) used previously we need 8 Hosts/Subnet

192.168.64.0/26

Requirement : 8 Hosts/Subnet

2^4 = 16 Hosts/Subnet Usable Hosts = 2^n (host bits) -2 = 2^4-2 = 16-2 = 14 Usable Hosts/Subnet New Mask = /32-/4 = /28 New IP: 192.168.64.0/28

192.168.64.0/28 (First NID)

192.168.64.1/26 (First Host IP)

192.168.1.80/26 (NID) 192.168.1.96/26 (NID)

192.168.1.112/26 (Last NID)

192.168.1.127/26 (Last BID)

192.168.1.128

Reference:

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